segunda-feira, 7 de dezembro de 2020

Maintenance traction project.

This project is about auxiliary electric motor for slow/maintenance speed operation.

We have 5 Bucket Belt elevators and only 3 of them are controlled by a Frequency Converters, the most powerful ones (110kW each). The smaller ones are direct start speed only, so the motor spins 1500 rpm.


Maintenance speed is highly necessary to be able to see the Buckets and the belt itself while it rolling.
This way I found the motoreductor out of another deactivated machine, produced support and traction elements.
The parameter of speed of this motoreductor is 99 rpm

The calculus I've used to get a desired speed are really simple.
Let's see the basic properties of the machine it self (mean elevator).
Motor 1470 rpm (a)
Gearbox reduction ratio 1:26 (b)
Revolutions per minute = a/b
Driving head pulley revolutions ≈ 56,54 rpm (z)
Driving head pulley ø 1,12 m (r*2)
With this data we can find:
V=2πrz/t Is the formula to get a speed
V = 2*π*0,56*56,54 / 60
V = 3,315678775

Belt speed ≈ 3,32 m/s

The desired speed of belt is about 0.45 m/s, as it is comfortable to work with.

Motoreductor speed 99 rpm
Driving head pulley revolutions ≈ 3,81 rpm (z)
When the motoreductor is coupled to reduction gearbox gives the next speed of belt:
V=(2πrz/t)
V = 2*π*0,56*3,81 / 60
V = 0,223294739

Belt speed ≈ 0,22 m/s

To increase the speed I needed to install chain gear transmission with increasing ratio 1*1,78

After all installed the speed became around 0,4m/s
Belt speed = 0,22*1,78≈0,4 m/s 


With this all job done I tried to start the system...
When I connected the cable the motor came with a huge kick then stabilized with normal speed. It happened every single start I've made. Clearly it needed a smooth starter.

In fact this motoreductor has been working with a Frequency Converter so this came as perfect as it is.


And after basic setup everything became as it expected to be... PERFECT!




This is how could look a low budget project.

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